Exam Name | NDA and NA |
Total Posts | 404 Posts |
Organization | UPSC |
Qualification | 12th Pass |
Application Process | Online |
Application Fee | ₹ 100/- |
Start Date | 15th May 2024 |
Last Date | 4th June 2024 |
Notification
UPSC NDA and NA (II) Recruitment 2024
Assam Career: Union Public Service Commission (UPSC) 2024 has recently invited application for the recruitment of 404 Vacancy for National Defence Academy & Naval Academy Examination (II), 2024 [Indian Naval Academy Course (INAC)]. The online application will start from 15th May 2024. Interested and eligible candidates can apply through online mode. https://upsc.gov.in.
Last Date: 04/06/2024.
Table of Contents
- 1 UPSC NDA and NA Recruitment Details
- 2 Eligibility Criteria of UPSC NDA and NA (II) Exam:
- 3 Application Fee of UPSC NDA and NA (II) Exam:
- 4 How to Apply for UPSC NDA and NA Recruitment?
- 5 Important Dates of UPSC NDA and NA (II) Exam 2024
- 6 Important Web-Links of UPSC NDA and NA (II) Vacancy:
- 7 FAQs of UPSC NDA and NA Recruitment
- 8 What is the starting date to apply online for UPSC NDA & NA Recruitment?
- 9 What is the last date to apply online for UPSC NDA & NA Recruitment?
- 10 How many posts are vacant under UPSC NDA & NA Recruitment?
UPSC NDA and NA Recruitment Details
Name of exam: National Defence Academy & Naval Academy Examination (II), 2024
Number of Vacancy: 404 posts
Vacancy Breakup:
- National Defence Academy: 370
- Naval Academy (10+2 Cadet Entry Scheme): 34
Exam Centres in Assam: Dispur
Eligibility Criteria of UPSC NDA and NA (II) Exam:
Age Limit: Only unmarried male/female candidates born not earlier than 2nd January 2006 and not later than 1st January 2009 are eligible.
Educational Qualification:
Army Wing of National Defence Academy: 12th Class pass of the 10+2 pattern of School Education or equivalent examination conducted by a State Education Board or a University.
Air Force and Naval Wings of National Defence Academy and for the 10+2 Cadet Entry Scheme at the Indian Naval Academy: 12th Class pass with Physics, Chemistry and Mathematics of the 10+2 pattern of School Education or equivalent conducted by a State Education Board or a University.
Candidates who are appearing in the 12th Class under the 10+2 pattern of School Education or equivalent examination can also apply for this examination
Application Fee of UPSC NDA and NA (II) Exam:
SC/ST Candidates: Exempted |
Sons of JCOs/ NCOs/ ORs: Exempted |
Other Candidates: ₹ 100/- (Rupees One Hundred Only) |
Payment Mode: Online/ Offline
How to Apply for UPSC NDA and NA Recruitment?
Interested and eligible candidates may apply online for UPSC Recruitment by visiting at official recruitment portal of UPSC. They may follow below mentioned steps.
➥ Scroll down, go to Important Web-Links section. |
➥ Click on Online Application Form link. |
➥ A new webpage will be opened. |
➥ Enter all your personal and educational details as required. |
➥ Upload your passport sized photograph and signature and other required documents. |
➥ Pay the application fee as per your category and at the end click on submit button. |
➥ Don’t forget to take a print of submitted application form. |
Important Dates of UPSC NDA and NA (II) Exam 2024
Starting date for submission of online application | 15th May 2024 |
Last date for submission of online application | 4th June 2024 |
Date of examination | 1st September 2024 |
Important Web-Links of UPSC NDA and NA (II) Vacancy:
Online Application Link | Click Here |
View official Advertisement | Click Here |
Official Website | Click Here |
For more correct information read the official notification carefully before apply.
FAQs of UPSC NDA and NA Recruitment
What is the starting date to apply online for UPSC NDA & NA Recruitment?
➲ The starting date to apply online for UPSC NDA & NA Recruitment is 15th May 2024.
What is the last date to apply online for UPSC NDA & NA Recruitment?
➲ The last date to apply online for UPSC NDA & NA Recruitment is 4th June 2024.
How many posts are vacant under UPSC NDA & NA Recruitment?
➲ The number of vacant posts under UPSC NDA & NA Recruitment is 404.